[03[0 k[02lc4C

Another useful expression can be obtained by subtracting equation (B) from (A). We obtain

2 rate| — 2 rate2 + 2 rate3 = 0

which by rearrangement and cancellation becomes rate3 = rate2 — ratej

It is known from experiment that rate2 (and rate3) is much larger than ratej, so the latter can be neglected here, giving simply rate3 — rate2

Using the expressions for these two reaction rates in terms of the concentrations of their reactants,

Continue reading here: K3[03 k2[0[02[M

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